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Uniform Isotope Labeling of Eukaryotic Proteins in Methylotrophic Yeast for High-Resolution NMR Studies – Extension to Membrane Proteins (Application Note 26)
Ying Fan, Lichi Shi, Vladimir Ladizhansky and Leonid S. Brown
Departments of Physics and Biophysics Interdepartmental Group
University of Guelph, 50 Stone Road East
Guelph, Ontario, N1G 2W1, Canada
- Uniform Isotope Labeling of Eukaryotic Proteins in Methylotrophic Yeast for High-Resolution NMR Studies – Extension to Membrane Proteins (Application Note 26)
CIL’s total quality assurance protocols and in-house manufacturing capabilities guarantee the highest standard of quality the first time and every time. These NMR Reference Standards have been evaluated and determined to meet or exceed industry requirements. We welcome your requests for custom formulations of other reference standards as well as alternative fill heights of existing reference standards.
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Frequently Asked Questions
Frequently Asked Questions
Does CIL offer reference standards with 40 mm fill height?
Yes we have a number of catalog products with a 40mm fill height. The catalog number ends in 40mm. Most (but not all) other NMR reference standard fill heights are 2 inches.
Does CIL manufacture custom NMR reference standards?
Yes, CIL is pleased to be able to offer custom products such as larger or smaller diameter NMR reference standards as well as different reference solutions. Please contact us with your request if you do not see your product of interest on the website.
How do you calculate the molarity of DLM-45, Sodium deuteroxide (D, 99.5%)?
DLM-45, Sodium deuteroxide (D, 99.5 %),
Molarity Calculation from Weight Percentage
DLM-45 has a concentration of 40 % NaOD in D2O, by weight (w/w). This means 40 g NaOD per 100 g of solution. The D2O accounts for the remaining 60 g of the solution.
What is the molarity of this solution? Molarity (M) is defined as the number moles of solute, per liter (L) of solution.
𝑀𝑜𝑙𝑎𝑟𝑖𝑡𝑦 ,𝑀.= ,𝑚𝑜𝑙𝑒𝑠 𝑜𝑓 𝑠𝑜𝑙𝑢𝑡𝑒-𝑙𝑖𝑡𝑒𝑟𝑠 𝑜𝑓 𝑠𝑜𝑙𝑢𝑡𝑖𝑜𝑛.
Taking 40 g of solute (NaOD) and its molecular weight (MW = 41.01 g/mol), we divide mass by MW to get 0.9754 mols for 40 g NaOD.
40 𝑔 𝑁𝑎𝑂𝐷 × ,1 𝑚𝑜𝑙 𝑁𝑎𝑂𝐷-41.01 𝑔 𝑁𝑎𝑂𝐷.=0.9754 𝑚𝑜𝑙𝑠 𝑁𝑎𝑂𝐷
We need the density of deuterium oxide, D2O, to find what volume 60 g will occupy. The density is 1.103 g/mL, so 1L D2O will weigh 1,103 g. We get the volume of D2O in L, by dividing the mass, 60 g D2O, by the mass of one liter, to get 0.0544 L D2O.
60 𝑔 ,𝐷-2.𝑂 ×,1 𝐿 ,𝐷-2.𝑂-1,103 𝑔 ,𝐷-2.𝑂 .=0.0544 𝐿 ,𝐷-2.𝑂
Assuming the NaOD occupies no additional volume in the solution, the volume of D2O is equal to the volume of the solution. Dividing 0.9754 mols NaOD by 0.0544 L gives 17.93 moles NaOD per L, about 18 M.
,0.9754 𝑚𝑜𝑙𝑠 𝑁𝑎𝑂𝐷-0.0544 𝐿.=17.93 ,𝑚𝑜𝑙𝑠-𝑙𝑖𝑡𝑒𝑟. ≈18 𝑀
We have assumed that slight variations of MW due to isotopic enrichment, and density variations with temperature can be ignored.
Kevin Millis, PhD
Senior Scientist, Application Development Manager
Kevin Millis, PhD, is the Senior Scientist and Market Development Manager for all NMR and Mass Spectrometry product lines. Kevin is responsible for Technical Services both internally and externally for all CIL customers as well as being responsible for the application and market development for the CIL products.More